Question #36699

How many moles of Naoh are in 26.7 ml of a 0.100 M NaOh solution?

Expert's answer

How many moles of NaOH are in 26.7 ml of a 0.100 M NaOH solution?

Solution:

The molar concentration (Ci)(C_i) is defined as the amount of a constituent (ni)(n_i) divided by the volume of the mixture VV:


Ci=niV=molelC_i = \frac{n_i}{V} = \frac{mole}{l}1l=1000 ml1l = 1000 \, mlV(NaOH)=0.0267 lV(NaOH) = 0.0267 \, l


Find the amount of the substance in the solution of NaOH:


n(NaOH)=c(NaOH)∗V(NaOH)n(NaOH) = c(NaOH) * V(NaOH)n(NaOH)=0.100 mole/l∗0.0267 l=0.00267 molen(NaOH) = 0.100 \, mole/l * 0.0267 \, l = 0.00267 \, mole


**Answer:** In 26.7 ml of a 0.100 M NaOH solution containing 0.00267 moles of NaOH

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