Question #35260

a chemistry student measured the boiling point of naphthalene (C10H8) at 231.0 degrees celsius. what is the percent error for this measurement if the literature value is 217.9 degrees celcius

Expert's answer

A chemistry student measured the boiling point of naphthalene (C₁₀H₈) at 231.0 degrees celsius. What is the percent error for this measurement if the literature value is 217.9 degrees celsius.

Solution:

The percent error is


δ=vvapproxv×100=vvapproxv×100\delta = \frac {\left| v - v _ {\text {approx}} \right|}{\left| v \right|} \times 100 = \left| \frac {v - v _ {\text {approx}}}{v} \right| \times 100


where δ is percent error, %; vv is absolute value of the measured magnitude, the dimensionality depend on measured magnitude; vapproxv_{\text{approx}} is approximate value of the measured magnitude, the dimensionality depend on measured magnitude.

Then vv is 217.9 degrees celsius (it is absolute or literature value) and vapproxv_{\text{approx}} is 231.0 degrees celsius (it is approximate or measured value).


δ=217.9231.0217.9×100=6.0%\delta = \left| \frac {217.9 - 231.0}{217.9} \right| \times 100 = 6.0 \%

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