a metal has a specific heat capacity of .899 Jg-1k-1 How much energy is required to raise the temperature of 2.00 Kg of the metal by 80 K
Solution:
q = m × C × ΔT
where:
q = amount of heat energy gained or lost by substance (J)
m = mass of sample (g)
C = specific heat capacity (J K−1 g−1)
ΔT = change in temperature (K)
m = 2.00 kg × (1000 g / 1 kg) = 2000 g
C = 0.899 J K−1 g−1
ΔT = 80 K
Thus,
q = (2000 g) × (0.899 J K−1 g−1) × (80 K) = 143840 J = 143.84 kJ
q = 143.84 kJ
Answer: 143.84 kJ of energy is required
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