Answer to Question #333010 in Inorganic Chemistry for Lean

Question

Chemcial Equation: C3H8 + O2 ( CO2 + H2O

If 50.0 grams of Cl2 gas is reacted with enough sodium hydroxide (NaOH), calculate the following:

Mass in grams of sodium hypochlorite (NaOCL) produced

Moles of sodium chloride (NaCl) produced

Chemical Equation: NaOH + Cl2 ( NaOCl + NaCl + H2O

Answer 1

2NaOH + Cl₂ = NaOCl + NaCl + H₂O

n(Cl₂) = m(Cl₂) / Mr(Cl₂) = 50.0 g / 71.0 g/mol = 0.704 mol

1 mol Cl₂ - 1 mol NaOCl

0.704 mol Cl₂ - x mol NaOCl

x = 0.704 mol

m(NaOCl) = n(NaOCl) * Mr(NaOCl) = 0.704 mol * 74.5 g/mol = 52.45 g

1 mol Cl₂ - 1 mol NaCl

0.704 mol Cl₂ - x mol NaCl

x = 0.704 mol