Answer to Question #316723 in Inorganic Chemistry for Vine

Question

Suppose 4.00 grams of H2 were used?how many grams of water would be produced?

Answer 1

The reaction of water formation is:

$2H_2+O_2=2H_2O$

The mole number of hydrogen and water is equal by the chemical reaction, thus the mole number of the given mass can be used directly to compute the mass of water.

$n(H_2)=n(H_2O)$

$\frac{m(H_2)}{M(H_2)}=\frac{m(H_2O)}{M(H_2O)}$

$m(H_2O=\frac{m(H_2)\times M(H_2O)}{M(H_2)} = \frac{4.00 g \times 18 g/mol}{2 g/mol}=36.00 g$