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Answer to Question #315392 in Inorganic Chemistry for wichi
Question #315392
if theres 180 grams of ci2 how many moles of FeCl3 can be produced?
Expert's answer
m(Cl2) = 180 g
n(FeCl3) - ?
Answer:
2Fe + 3Cl2 -> 2FeCl3
n(Cl2)= m/M = 180g/71g/mol = 2.53mol
n(FeCl3) = 3/2 n(Cl2) = 3.8 mol
Answer: 3.8 mol
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