Question

If Bk-200 loses a neutron, what is left?

Answer 1

It is some nuclear reaction.

The process when Berkelium-200 loses neutron is next:

$${ } _ { 9 7 } ^ { 2 0 0 } \mathrm { B k } - { } _ { 0 } ^ { 1 } \mathrm { n } \rightarrow { } _ { 9 7 } ^ { 1 9 9 } \mathrm { B k }$$

It means that when Berkelium-200 loses neutrons it becomes an isotope Berkelium-199.