Question #29763

what cation would be present in a solution which forms a precipitate when added to sodium carbonate and sodium sulfate solutions but which gives no visible reaction with sodium chloride or sodium hydroxide solution

Expert's answer

Ba2+\mathrm{Ba}^{2+} is one of the most congruent ion that forms a precipitate when added to sodium carbonate and sodium sulfate solutions but which gives no visible reaction with sodium chloride or sodium hydroxide solution.

The reactions for processes with precipitate forming:


Ba(aq)2++Na2SO4(aq)2Na+(aq)+BaSO4(s) (white precipitate)\mathrm{Ba}^{2+}_{\mathrm{(aq)}} + \mathrm{Na_2SO_4}_{\mathrm{(aq)}} \rightarrow 2\mathrm{Na^+}_{\mathrm{(aq)}} + \mathrm{BaSO_4}_{\mathrm{(s)}} \downarrow \text{ (white precipitate)}Ba(aq)2++Na2CO3(aq)2Na+(aq)+BaCO3(s) (white precipitate)\mathrm{Ba}^{2+}_{\mathrm{(aq)}} + \mathrm{Na_2CO_3}_{\mathrm{(aq)}} \rightarrow 2\mathrm{Na^+}_{\mathrm{(aq)}} + \mathrm{BaCO_3}_{\mathrm{(s)}} \downarrow \text{ (white precipitate)}


The reaction for process with no visible reaction:

For Ba2++NaCl\mathrm{Ba}^{2+} + \mathrm{NaCl} there is no some reaction


Ba(aq)2++2NaOH(aq)=2Na+(aq)+Ba(OH)2(aq)\mathrm{Ba}^{2+}_{\mathrm{(aq)}} + 2\mathrm{NaOH}_{\mathrm{(aq)}} = 2\mathrm{Na^+}_{\mathrm{(aq)}} + \mathrm{Ba(OH)}_{2\mathrm{(aq)}}

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