Question #29601
1) Hydrogen iodide 0.2 moles each of H2 and I2 into a 1litre flask. Calculate the equilibrium contact value (Kc) for the reaction when a) 0.0z
7 moles per litre eaach of H2 and I2 was present at equilibrium. B) 0.20 moles per litre each of H2 and I2 had each at the time equilibrium was established.
7 moles per litre eaach of H2 and I2 was present at equilibrium. B) 0.20 moles per litre each of H2 and I2 had each at the time equilibrium was established.
Expert's answer
The reaction is:
H2 + I2 = 2HI
A)
The concentrations are:
C(H2) = 7 / 1 = 7 M
C(I2) = 7/ 1 = 7 M
C(HI) = 7*2 / 1 = 14 M
Kc = [HI]2/[H2][I2]
so the equilibrium contact value will be
Kc = 142 / 7*7 = 4
B)
The concentrations are:
C(H2) = 0.2 / 1 = 0.2 M
C(I2) = 0.2 / 1 = 0.2 M
C(HI) = 0.2 *2 / 1 = 0.4 M
Kc = [HI]2/[H2][I2]
so the equilibrium contact value will be
Kc = 0.42 / 0.2*0.2 = 4
Answer: 4
H2 + I2 = 2HI
A)
The concentrations are:
C(H2) = 7 / 1 = 7 M
C(I2) = 7/ 1 = 7 M
C(HI) = 7*2 / 1 = 14 M
Kc = [HI]2/[H2][I2]
so the equilibrium contact value will be
Kc = 142 / 7*7 = 4
B)
The concentrations are:
C(H2) = 0.2 / 1 = 0.2 M
C(I2) = 0.2 / 1 = 0.2 M
C(HI) = 0.2 *2 / 1 = 0.4 M
Kc = [HI]2/[H2][I2]
so the equilibrium contact value will be
Kc = 0.42 / 0.2*0.2 = 4
Answer: 4
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#340153 on Dec 2023
#340153 on Dec 2023