Question #290161

Calculate



The number of moles



The amount in grammes of HCL that must be added to 500cm^3



Of water to give a solution with pH 3

1
Expert's answer
2022-01-24T19:26:01-0500

[H+]=10pH=103=0.001 M[H^+]=10^{-pH}=10^{-3}=0.001\ M


HCl is a strong monoprotic acid, so [HCl] = [H+] = 0.001 M


n(HCl)=500 cm3×0.001 mol1 L×1 L1000 cm3=0.0005 moln(HCl)=500\ cm^3\times\frac{0.001\ mol}{1\ L}\times\frac{1\ L}{1000\ cm^3}=0.0005\ mol


m(HCl)=0.0005 mol×36.46 g1 mol=0.0182 gm(HCl) =0.0005\ mol\times\frac{36.46\ g}{1\ mol}=0.0182\ g


Answer: 0.0005 mol; 0.0182 g


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS