Calculate
The number of moles
The amount in grammes of HCL that must be added to 500cm^3
Of water to give a solution with pH 3
[H+]=10−pH=10−3=0.001 M[H^+]=10^{-pH}=10^{-3}=0.001\ M[H+]=10−pH=10−3=0.001 M
HCl is a strong monoprotic acid, so [HCl] = [H+] = 0.001 M
n(HCl)=500 cm3×0.001 mol1 L×1 L1000 cm3=0.0005 moln(HCl)=500\ cm^3\times\frac{0.001\ mol}{1\ L}\times\frac{1\ L}{1000\ cm^3}=0.0005\ moln(HCl)=500 cm3×1 L0.001 mol×1000 cm31 L=0.0005 mol
m(HCl)=0.0005 mol×36.46 g1 mol=0.0182 gm(HCl) =0.0005\ mol\times\frac{36.46\ g}{1\ mol}=0.0182\ gm(HCl)=0.0005 mol×1 mol36.46 g=0.0182 g
Answer: 0.0005 mol; 0.0182 g
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