If 6.12 mol of ethane (C2H6) undergo combustion according to the unbalanced equation C2H6 + O2 −→ CO2 + H2O , how many moles of O2 is required? Answer in units of mol.
The balanced equation is;
2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g)
Mole ratio of ethane to oxygen is 2:7
Moles of ethane = 6.12
Therefore, moles of oxygen = (6.12/2 x 7) = 21.42
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