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Answer to Question #283596 in Inorganic Chemistry for Nilesh

Question #283596

Natural boron is composed of two isotopes: 19.78% boron-10 (atomic mass = 10.0129 amu) and 80.22% boron-11 (atomic mass = 11.0093 amu). What is the average atomic mass of naturally occurring boron?

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Expert's answer
2021-12-30T12:44:03-0500

Average atomic mass=(19.78%*10.0129amu + 80.22%*11.0093amu)/100%=10.8122amu


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