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Answer to Question #280058 in Inorganic Chemistry for Retta
Question #280058
Assuming a total pressure of 9.5 atm, what is the partial pressure of each component in the mixture of 98% helium and 2.0% oxygen breathed by deep sea divers? How does the partial pressure of oxygen in diving gas compare with its partial pressure in normal air?
Expert's answer
- Mass of oxygen m
- O
- 2
- =
- 2.0
- g
- mO2=2.0 g
- Mass of helium, m
- H
- e
- =
- 98.0
- g
- mHe=98.0 g
- Total pressure, {eq}\rm P_t = 0.2125atm
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