Answer to Question #279072 in Inorganic Chemistry for Anne

Question

A gas sample is initially at 3.3 atm and 8.7 L. If the volume is adjusted to 7.7, what is the new pressure of the gas sample? (Assume the sample is maintained in a closed container with constant temperature).

Answer 1

P₁ = 3.3atm

V₁ = 8.7L

V₂ = 7.7L

P₂ = ?

Using Boyle's law

PV=k(constant)

P₁V₁ = P₂V₂

3.3*8.7= P₂*7.7

28.71 = P₂*7.7

P₂= 28.71/7.7

P₂ = 3.73atm

The answer is consistent with Boyle's law because when volume decreases, pressure increases(inverse relation)