Question

Write the net ionic equation for the following reactions:

A. Zn(s) + Pb(NO3)2(aq) = Zn(NO3)2(aq) + Pb(s)

B. 2 KOH(aq) + H2SO4(aq) = K2SO4(aq) + 2 H2O(I)

C. 2 FeCl3(aq) + SnCl2(aq) = 2 FeCl2(aq) + SnCl4(aq)

Answer 1

For the given reaction

​$Zn_{(s)}+Pb(NO_3)_{2(aq)} \rightarrow Pb_{(s)}+Zn(NO_3)_{2(aq)}$

a balanced net ionic equation is

​$Zn_{(s)}+Pb^{2+}_{(aq)} \rightarrow Pb_{(s)}+Zn^{2+}_{(aq)}$

During the reaction

Zn_(s) is oxidized and it is the reducing agent,

Pb(NO₃)_2(aq) is reduced and it is the oxidizing agent.

The balanced half reactions for the oxidation and reduction are following:

$Zn_{(s)} \rightarrow Zn^{2+}_{(aq)} + 2e^-$ (oxidation half-reaction)

$Pb^{2+}_{(aq)} +2e^- \rightarrow Pb_{(s)}$ ​ (reduction half-reaction)