Answer to Question #268533 in Inorganic Chemistry for Deewhy

Question

Preparation of cadmium

Answer 1

to prepare 1000 ppm of cadmium using CdCl2.H2O

I got different suggestions.

1) Dissolve 2.036 g of CdCl2 in 1 litre of deionized water

2)

1000 ppm = 1000mg/l Cd * 1 g Cd/1000 mg Cd * 201.32/112.411 = 1.790 g Cd/l H2O

where 201.32 = mol wt of cdCl2.H2O

112.411 = elemental mass of Cd

( suggestion was we are to prepare ppm solution of cd and not CdCl2.H2O)

3) Cd (in CdCl2.H2O) equivalent to 1 g elemental Cd

= Mol wt of CdCl2.H2O*100/ At Wt of Cd * Purity of CdCl2.H2O

= 201.32*100/112.411* 98 (% purity of CdCl2.H2O)

= 1.8274 g/l