Answer to Question #267004 in Inorganic Chemistry for rei

Question

Calculate the mass of solid sodium carbonate when 16.8 grams of sodium hydrogencarbonate is heated strongly until there is no further change. (3pts) 2NaHCO3(s) -- Na2CO3(s) + CO2 (g) +H2O (l) *

Answer 1

$2NaHCO_3 (heat) \to Na_2CO_3+CO_2+H_2O$

Moles of sodium hydrogen carbonate $=\frac{16.8}{23+1+12+16+16+16}=0.2$

Mole ratio, sodium hydrogen carbonate : sodium carbonate=2:1

Moles of sodium carbonate = $0.2/2=0.1$

Mass of sodium carbonate = no. of mole $\times$ molar mass=$0.1\times (23+23+12+16+16+16)=10.6g$