Question

Mg+CO2=MgO+C
a] balance the equation
b] determine the relative mass of Magnesium
c]2.40 of Mg is reacted with CO2. Calculate:
i] number of moles of Mg in 2.40. Show working
ii]the mass of carbon produced

Answer 1

$\mathrm{Mg + CO2 = MgO + C}$

a] balance the equation

b] determine the relative mass of Magnesium

c] 2.40 of Mg is reacted with CO2. Calculate:

i] number of moles of Mg in 2.40. Show working

ii] the mass of carbon produced

**Answer:**

a] balance the equation: $2\mathrm{Mg} + \mathrm{CO}_{2} = 2\mathrm{MgO} + \mathrm{C}$;

b] the relative mass of Magnesium in these equation is: $2 \cdot \mathrm{Ar(Mg)} = 2 \cdot 24 = 48\mathrm{g}$;

c]

i] the $24\mathrm{g}$ of $\mathrm{Mg}$ is 1 mole, so $2.4\mathrm{g}$ of $\mathrm{Mg}$ is 0.1 mole;

ii] if react 2 mole of Mg 1 mole or $12\mathrm{g}$ of C will produce. So, if react 0.1 mole of Mg 0.6 g of C will produce.