Answer to Question #264034 in Inorganic Chemistry for lilly

Question

Suppose 100 g of PbS is reacted with 4g of C and 20g O₂.

Find the limiting reactant for this reaction.   

Answer 1

2PbS(s) + 2C(s) + 3O₂(g) → 2Pb(s) +2CO(g) + 2SO₂(g)

n(PbS) = 100 g / (2 *239.3 g/mol) = 0.21 mol

n(C) = 4 g / (2*12 g/mol) = 0.17 mol

n(O₂) = 20 g / (3*32 g/mol) = 0.21 mol

C is limiting reactant