Question

1. Express the oxidation and reduction half reactions of the following.

(MnO₄^-+) to MnO₂(s)

Answer 1

The oxidizing agent is Mn and the element that gets reduced is O.

The half-cell oxidation reaction is

$Mn_2^+ + 2H_2O = MnO_2 +4H^+ + 2e$

and the half-cell reduction reaction is

$\frac{1}{4} O_2 + H^+ + e = ½ H_2O.$