Question

1. What is the pH of a solution of HCl with a concentration of 1.2 X 10-3 M?

Answer 1

Concentration of HCl $C = 1.2×10^{-3}$

$pH = -log[C]$

$=-log[1.2×10^{−3}]$

     $= -[log1.2 + log10^{-3}]$

  $= -[0.079 - 3log10]$

    $= -[0.079 - 3]$

$pH = 2.921$