M(water) = 18 g/mol
n(water) "= \\frac{18}{5.20} = 3.46 \\;mol"
Table value of ΔH(vaporization) for water at 100 °C is 40.657 kJ /mol
We have 3.46 mol,
"Q = 3.46 \\times 40.657 = 140.73 \\;kJ"
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