Answer to Question #260457 in Inorganic Chemistry for Lyn²

Question

1. A mixture of BaO and CaO weighing 2.212 g is transformed into mixed sulfates (BaSO4 and CaSO4) weighing 5.023 g.

a. Calculate the number of grams of CaO and of BaO in the original mixture.

b. What weight of limestone should be taken so that 1/20 the number of milligrams of CaSO4 obtained will represent the percentage of CaO in the mineral?

Answer 1

Weight percent of Ba = (Weight of Ba / Total weight)×100

Weight of Ba = 137 g per mol

Weight of BaO = 153 g

Weight percentage = (137/153)*100

= 89.5 %

153 g ----------- 89.5 %

therefore for 2.00 g --- (89.5/153)(2.00)

= 1.17%

Weight of Ca --- 40 g

Weight of CaO -- 56 g

Weight percentage = (40/56)100

= 71.4%

56 g --------------- 71.4 %

2.0 g ---------- (71.4/56)×2.0

= 2.56%