Question

Calculate the molar concentration of solute in the following:

1. 7.59g of NH₃ in 1.500L solution.
2. 0.291g of H₂SO₄ in 8.65L solution.
3. 85.2g of NaOH in 5.00L solution.
4. 31.25g of NaCl in 2.00L solution.
5. 6mg of atmospheric N₂ in water with volume of 2.00L.

Answer 1

Molarity of $NH_3=[\frac{7.59}{17.031}]÷1.500=0.297M$

$H_2SO_4=[\frac{0.291}{ 98.079 }]÷8.65=0.00034M$

$NaOH=[\frac{85.2} { 39.997 }]÷5.00=0.43M$

$NaCl=[\frac{31.25}{ 58.44 }]÷2.00=0.267M$