Answer to Question #258720 in Inorganic Chemistry for Abang

Question

Lead metal is obtained from lead sulphide through the following reaction:

          2PbS(s) + 2C(s) + 3O₂(g) → 2Pb(s) +2CO(g) + 2SO₂(g)

Suppose 100 g of PbS is reacted with 4g of C and 20g O₂.

Find the limiting reactant for this reaction

Answer 1

Molar mass of PbS = 239.3

= 100/239.3

= 0.418 moles

Mole ratio = 2:2

= 0.418 moles of Pb

Molar mass of Pb = 207.2

= 207.2×0.418

= 86.59g