Question

calculate the number of grams of aluminum sulfate produce if 3.85 g of aluminum is added to 6.85 g of sulfuric acid.

Answer 1

2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂

Moles of aluminum = 3.85 ÷ 26.99 =0.42 moles

Moles of sulfuric acid = 6.85 ÷98.079 = 0.07moles

Molar mass of aluminium sulfate : 342.15 g/mol

Mass = $342.15 × \frac{0.42}{2}=71.85grams$

Mass$=342.15 × \frac{0.07}{3}=7.9835grams$