Answer to Question #252227 in Inorganic Chemistry for Nic

Question

Calculate the number of grams of aluminum sulfate produced if three point 85 grams of aluminum is added to six point 85 grams of sulfuric acid.

Answer 1

2Al(s)+3H2SO4(aq)→Al2(SO4)3(aq)+3H2(g)

Molar mass of Al= 26.981539

85/26.981539= 3.15mol

Molar mass of H2SO4= 98.079

85/98.079= 0.87mol

Mole ratio of Al:Al2(SO4)3= 2:1

Mole ratio of H2SO4:Al2(SO4)3= 3:1

= 1/2+1/3= 5/6

Molar mass of Al2(SO4)3= 342.15 g/mol

342.16×5/6

= 285.13g