2013-02-25T12:55:14-05:00
A balloon containing 0.56 mol of helium has a volume of 10.0 L. What volume will the balloon occupy if helium is lost and only 0.21 mol remain?
1
2013-02-27T06:00:27-0500
According to the ideal gas law pV1 = n1 RT - at the beginning pV2 = n2 RT - after part of helium is lost p (pressure), T(temperature), R (universal gas constant) - don't change V1 , V2 - volumes n1 , n2 - moles (pV1 /pV2 ) = (n1 RT)/(n2 RT) V1 /V2 = n1/n2 After helium is lost the volume is V2 = (V1 n2 )/n1 V2 = (10.0 x 0.21)/ 0.56 = 3.75 L Answer: V2 = 3.75 L
Need a fast expert's response?
Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS !
Comments