How many grams of salt are needed to make 637 g of saltwater that is 32.0% salt by mass?
**Solution:**
Assume that 637 g is 100%, so
X g - 32.0%.
From this it follows that x=637⋅32100=203.84x = \frac{637 \cdot 32}{100} = 203.84x=100637⋅32=203.84 g
**Answer:** The mass of salt is 203.84 g.
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