Answer to Question #244178 in Inorganic Chemistry for Awit

Question

In analyzing the crude fiber content of a certain food, 0.313N NaOH is required. What is the mass of NaOH pellets needed to prepare 500ml of the solution? What is the molarity of the solution?

Answer 1

f(NaOH)=1

Then:

c_N(NaOH) = c(NaOH) = 0.313Mc

N

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(NaOH)=c(NaOH)=0.313M

n(NaOH) = c(NaOH)V(NaOH)n(NaOH)=c(NaOH)V(NaOH)

n(NaOH) = 0.313M*0.5L = 0.1565moln(NaOH)=0.313M∗0.5L=0.1565mol

m(NaOH) = nM = 0.1565mol*39.997g/mol =6.2595g = 6.26gm(NaOH)=nM=0.1565mol∗39.997g/mol=6.2595g=6.26g

ANSWER: 0.313M; 6.26g