Question

0.5 M KOH is one of the reagents needed in the qualitative determination of stimulant cathartic anthraquinone in plants. How many grams of KOH are required to prepare 1L solution? MW KOH = 56 g/mol

Answer 1

$C=\frac{n}{V}$

$n=C\times V=0.5\times1=0.5$ mol

$m=n\times M=0.5\times56=28$  g