Question

What is the boiling point of a solution contains 0.058 mol of sucrose in 0.20 kg of water?

Answer 1

When a solute is added in a solvent the boiling of solvent is elevated.

This elevation in boiling point (∆T_b) is given by the formula

$∆T=K_bm$

Boiling point constant = 0.512 °C/ molar for water

Here solute is glucose & solvent is water.

Boiling point of pure water is 100°C

$(T-100°C)=0.512°C/molal×\frac{0.058mol}{0.20kg}$

$T=100°C+ 0.14848=100.14848°C$