Question

'Suppose you have a 0.10 M solution of AlBr3. What is the concentration of each ion?

Answer 1

AlBr_3 → Al^{+3} + 3Br^- \\ [Al^{+3}] = [AlBr_3] = 0.10 \; M \\ [Br^-] = 3 \times [AlBr_3] = 3 \times 0.10 \;M = 0.30 \;M