Question #240805

How much heat is lost when a solid aluminum ingot with a mass of 4,110 g cools from 660.0

Expert's answer

heat=nCp delta T

1.molar mass of al=27

moles for 4110 gms=152.2 moles

heat =nCp delta T

=152.2×.9025×(660-25)=87.223Kj


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