Calculate the number of moles of solute present in 255 mL of 0.250 M CaBr 2.
Proportion:
0.250 mol – 1000 mL
x mol – 255 mL
x=0.250×2551000=0.06375 molx = \frac{0.250 \times 255}{1000}= 0.06375 \;molx=10000.250×255=0.06375mol
Answer: 0.0637 mol
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