Question #236001

Calculate the number of moles of solute present in 255 mL of 0.250 M CaBr 2.


1
Expert's answer
2021-09-12T23:16:44-0400

Proportion:

0.250 mol – 1000 mL

x mol – 255 mL

x=0.250×2551000=0.06375  molx = \frac{0.250 \times 255}{1000}= 0.06375 \;mol

Answer: 0.0637 mol


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