Answer to Question #236001 in Inorganic Chemistry for Bub

Question

Calculate the number of moles of solute present in 255 mL of 0.250 M CaBr 2.

Answer 1

Proportion:

0.250 mol – 1000 mL

x mol – 255 mL

$x = \frac{0.250 \times 255}{1000}= 0.06375 \;mol$

Answer: 0.0637 mol