Putting molar gas volume =24000cm3 and molar mass of sulphite =126g, mass of the sulphite used can be calculated as follows.
number of moles of sulphur (iv) oxide =24000cm3960cm3×1mole=0.04moles
Equation:
Na2SO3(s)+2HClaq→2NaClaq+SO2(g)+H2O(l)
mole ration Na2SO3:SO2 is 1:1
number of moles of Na2SO3=0.04moles
mass of Na2SO3=126gmol−1×0.04=5.04g
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