Question #233690

Find the mass of water in 300. grams of a 2.80m KCl solution. The answer is 248 g H2O but I'm not sure how to work out the problem.


1
Expert's answer
2021-09-06T02:35:35-0400

2.80m solution means that 2.80 moles of KCl is dissolved per 1 kg of solvent.
This means that 2.80 moles 74.5 g/mol=208.6 g2.80\ moles\ *74.5\ g/mol=208.6\ g of KCl is dissolved per 1000 g of water.

Solute/solvent mass ratio=208.6 g1000 g=0.2086Solute/solvent\ mass\ ratio=\dfrac{208.6\ g}{1000\ g}=0.2086


Let the mass of water in 300 grams of the solution be x, then the mass of KCl is 300-x and 300xx=0.2086;300x=0.2086x;1.2086x=300;x=3001.2086=248.22.\dfrac{300-x}{x}=0.2086;300-x=0.2086x;1.2086x=300;x=\dfrac{300}{1.2086}=248.22.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS