Find the mass of water in 300. grams of a 2.80m KCl solution. The answer is 248 g H2O but I'm not sure how to work out the problem.
1
Expert's answer
2021-09-06T02:35:35-0400
2.80m solution means that 2.80 moles of KCl is dissolved per 1 kg of solvent. This means that 2.80moles∗74.5g/mol=208.6g of KCl is dissolved per 1000 g of water.
Solute/solventmassratio=1000g208.6g=0.2086
Let the mass of water in 300 grams of the solution be x, then the mass of KCl is 300-x and x300−x=0.2086;300−x=0.2086x;1.2086x=300;x=1.2086300=248.22.
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