Question #22875

A significant contribution to atmospheric Carbon dioxide levels comes from the thermal decomposition of limestone in the manufacture of cement and of lime for agricultural purposes.

Cement works roast 1000 million tonnes of limestone per year and a further 200 million tonnnes is roasted in kilns to make lime.

What is the total annual mass output of carbon dioxide (in million tonnes) from these two processes?

Expert's answer

A significant contribution to atmospheric Carbon dioxide levels comes from the thermal decomposition of limestone in the manufacture of cement and of lime for agricultural purposes.

Cement works roast 1000 million tones of limestone per year and a further 200 million tones is roasted in kilns to make lime.

What is the total annual mass output of carbon dioxide (in million tones) from these two processes?

Solution:

The thermal decomposition of limestone is:


CaCO3CaO+CO2\mathrm{CaCO_3} \rightarrow \mathrm{CaO} + \mathrm{CO_2}


Using atomic masses from the periodic table, we will find the following:


M(CaCO3)=40+12+16.3=100 g/mol=100 kg/kmolM(CaO)=40+16=56 g/mol=56 kg/kmol;M(CO2)=12+16.2=44 g/mol=44 kg/k/mol.\begin{array}{l} \mathrm{M}(\mathrm{CaCO_3}) = 40 + 12 + 16.3 = 100\ \mathrm{g/mol} = 100\ \mathrm{kg/kmol} \\ \mathrm{M}(\mathrm{CaO}) = 40 + 16 = 56\ \mathrm{g/mol} = 56\ \mathrm{kg/kmol}; \\ \mathrm{M}(\mathrm{CO_2}) = 12 + 16.2 = 44\ \mathrm{g/mol} = 44\ \mathrm{kg/k/mol}. \end{array}


If we roast 100 kg100\ \mathrm{kg} of limestone we obtain 44 kg44\ \mathrm{kg} of CO2\mathrm{CO_2}, for the equation of reaction. From 1000 million tones of limestone we obtain:


m(CO2)=100044100=440 million tones\mathrm{m}(\mathrm{CO_2}) = \frac{1000 \cdot 44}{100} = 440\ \text{million tones}


When we prepare 56 kg lime (CaO) we also obtain 44 kg CO244\ \mathrm{kg}\ \mathrm{CO_2}. If we prepare 200 million tones CaO we also obtain the mass of CO2\mathrm{CO_2}:


m(CO2)=2004456=157.14 million tones.\mathrm{m}(\mathrm{CO_2}) = \frac{200 \cdot 44}{56} = 157.14\ \text{million tones}.


The total mass CO2\mathrm{CO_2} output from two processes:


m(CO2)=440.0+157.4=597.4 million tones.\mathrm{m}(\mathrm{CO_2}) = 440.0 + 157.4 = 597.4\ \text{million tones}.

Answer:

The total mass CO2\mathrm{CO_2} output from two processes is 597.4 million tones.

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