Answer to Question #223325 in Inorganic Chemistry for Rashinda mz

Question

ALuminum sulphide is produced from a reaction of the elements Al and S according to the reaction 2Al_(s) + 3S_(g)  → Al₂S₃ . Given that the mass of aluminum is defined by a function m_A such that t(m_Al) = [ m_Al 4.1

41/10 m_Al ] and that t( m_Al ) is a singular matrix. The mass of sulfur that reacted was equivalent to the P^OH of 3.981 x 10^-7M solution of a base. What is the mass of the product formed?

A. 10.41g B. 102.6g C. 25.2g D. 40.5g

Answer 1

B. 102.6g