According to equation;
2H2(g)+O2(g)→2H2(l)2H_{2(g)}+O_{2 (g)} \to 2H_{2(l)}2H2(g)+O2(g)→2H2(l)
n(H2O) = n(PCB) = 10.0 mol
Answer: 2(H2O) = 20.0 mol of O2
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