Question #22102
Predict the mass of hydrogen gas produced when 2.73 g of aluminum reacts in a single replacement reaction with excess sulphuric acid.
Expert's answer
2Al+ 3H2SO4 = Al2(SO4)3 + 3H2
First, look for the amount of substance aluminum oxide:
n(Al2O3)=m/M
n(Al2O3)= 100g/ 102g/mol = 0.9999 mol
1 mol Al2O3 ----> 2mol Al
n(Al)= 1,9998 mol
m(Al)= n*M
m(Al) = 1,9998mol*27 g/mol = 53,99 g
Answer: 53,99g
First, look for the amount of substance aluminum oxide:
n(Al2O3)=m/M
n(Al2O3)= 100g/ 102g/mol = 0.9999 mol
1 mol Al2O3 ----> 2mol Al
n(Al)= 1,9998 mol
m(Al)= n*M
m(Al) = 1,9998mol*27 g/mol = 53,99 g
Answer: 53,99g
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