Question

What is the molar concentration of a solution containing 10.0 g of NaOH in 250 mL of solution?

Answer 1

Themolar concentration of the solution can be found for the formula
C_m = n / V(solution);
So if we have 10.0 g of NaOH, we can find it's amount of substance
n(NaOH) = m(NaOH) / M(NaOH);
M(NaOH) = 23 + 16 + 1 = 40 g/mol;
n(NaOH) = 10g / 40 g/mol = 0.25 moles
So the molar concentration of solution will be
C_m(NaOH) = 0.25 moles / 0.25 L = 1mol/L