Question

1. What volume of a 6.0 M NaOH solution is needed to produce 3.0 L of a 0.1 M solution?

Answer 1

Needed n(NaOH) $= 0.1 \times 3.0 = 0.3 \;mol$

Proportion:

6.0 mol – 1000 mL

0.3 mol – x

$x = \frac{0.3 \times 1000}{6.0}=50 \;mL$

Answer: 50 mL