Answer to Question #218926 in Inorganic Chemistry for Dhenchu dhenchu

Question #218926
What is the molality of Ammonia in a solution containing 0.85 g of NH3 in 100 cm3 of a liquid of density 0.85 g/cm3
1
Expert's answer
2021-07-20T13:39:01-0400

find the formula:

"n=\\frac{m}{M}"

find the mass of solution

"m(s)= 100 cm\u00b3 \\times0.85 g \/cm\u00b3 = 85.0 g"

find mass of the water: the solution contains 0.85 g NH3:

"m(w)= 85.0 g (s)- 0.85 g (NH3) = 84.15 g (w)"

find mass of NH3 in 1000 g water:

"m(NH3)=\\frac{ 1000 g}{84.15 g}\\times 0.85 g (NH3) = 10.1 g (NH3)"

molar mass NH3 = 17.0306 g/mol

find Mol NH3 in 10.1 g:

"n= \\frac{10.1g}{ 17.0306 g\/mol} = 0.593 mol NH3"



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