1. Fe3+ + e- → Fe2+ Eo = +0.77 V
Fe2+ + 2e- → Fe Eo = -0.44 V
The first half-reaction represents the reduction of iron (III) to iron (II). The second half-reaction represents the reduction of iron (II) to iron metal. We can find the reduction potential of our desired reaction by adding these two half-reactions and eliminating common species on both sides. The reduction potential of our desired reaction will then be the sum of the reduction potentials of these two half-reactions.
=0.77−0.44 = 0.33V
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