Question #21249
"What would the mass of air be inside a hot air balloon that has the volume of 5.25 x 10^4 L. The temperature of the air inside is 30 degrees celsius and the pressure is 95.5 kPa. Assume the composition of air is 80% nitrogen gas and 20% oxygen gas to determine the molar mass of air."
Expert's answer
For answering this question you need to use the next law:
PV = nRT,where
P-pressure = 95.5 kPa
V- volume = 5,25*10^4 L
R - constant = 8.31
T- temperature = 273+30=303 C
n = PV/RT
n = 95.5*5,25*10^4/ 8.31* 303 = 1991.22mol
"Mw" of air= 0.8*28+0.2*32=28.8
n = m/Mw => m = n*Mw = 1991.22* 28.8 =57.347 kg
PV = nRT,where
P-pressure = 95.5 kPa
V- volume = 5,25*10^4 L
R - constant = 8.31
T- temperature = 273+30=303 C
n = PV/RT
n = 95.5*5,25*10^4/ 8.31* 303 = 1991.22mol
"Mw" of air= 0.8*28+0.2*32=28.8
n = m/Mw => m = n*Mw = 1991.22* 28.8 =57.347 kg
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