Question

Q. One litre of CO2 is passed over hot coke. The volume becomes 1.4 litre. The composition of product is-
(i) 0.6 ltr CO (ii) 0.8 ltr of CO2 (iii)0.6 ltr of CO2 and 0.8 ltr of CO (iv) None

Answer 1

Equation of the reaction:
CO₂ + C = 2CO
According to equation, when 1 litre of CO₂ reacts with 1 mol of coke, twolitres of CO are formed. Our mixture of gases has volume 1.4 L. Thus it is
composed from CO and non-reacted CO₂.
If x litres of CO₂ are reacted, 2x liters of CO are formed. Total volume ofmixture is the sum of CO₂ and CO volumes:
V(mixture) = V(new volume CO₂) + V(CO) = 1.4 L
V(new volume CO₂) = V(initial volume CO₂) - V(reacted CO₂) = (1 - x) L
V(CO) = 2x
So, we have equation:
1.4 = 1 - x + 2x
The solution is x = 0.4 L
Thus, the mixture consist from 1-0.4=0.6 L of CO2 and 2*0.4=0.8 L of CO (iii)
Answer: (iii)
The composition of product is 0.6 ltr of CO2 and 0.8 ltr of CO.