Calculate the total amount of energy (in kJ) necessary to raise the temperature of 2.00 L of ethanol (density
= 0.7849 g/cm3
) from 18 0C to its boiling point (78.3 0C) and then to fully vaporize the liquid. Assume that
it is a closed system where no heat exchange with the surroundings take place.
(Given: Cethanol = 2.44 J/g·K; heat of vaporization of ethanol at 78.3 0C = 38.56 kJ/mol.)
[5 marks)
The value of heat is "q=mC\\Delta T"
"q=1569 \u00d72.44\u00d7(78.3-18)"
"q=230.967kJ"
Heat required to vaporize "=34.10 \u00d7\\Delta H _{vap}" =1315.23kJ
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