Answer to Question #210817 in Inorganic Chemistry for Merlyn

Question #210817

Calculate the total amount of energy (in kJ) necessary to raise the temperature of 2.00 L of ethanol (density

= 0.7849 g/cm3

) from 18 0C to its boiling point (78.3 0C) and then to fully vaporize the liquid. Assume that 

it is a closed system where no heat exchange with the surroundings take place.

(Given: Cethanol = 2.44 J/g·K; heat of vaporization of ethanol at 78.3 0C = 38.56 kJ/mol.)

[5 marks)


1
Expert's answer
2021-06-28T08:15:39-0400

The value of heat is q=mCΔTq=mC\Delta T


q=1569×2.44×(78.318)q=1569 ×2.44×(78.3-18)


q=230.967kJq=230.967kJ


Heat required to vaporize =34.10×ΔHvap=34.10 ×\Delta H _{vap} =1315.23kJ


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