Question #20410

a solution was prepared by mixing 10 mole of alcohol and 10 mole of water. what is the composition of solution expressed in mole fraction

Expert's answer

Task:

A solution was prepared by mixing 10 mole of alcohol and 10 mole of water. What is the composition of solution expressed in mole fraction?

Solution:

C2H5OH+H2O=C2H5OH+H2OC_{2}H_{5}OH + H_{2}O = C_{2}H_{5}OH + H_{2}O (Ethanol doesn't react with water)

The mole fraction xix_{i} is defined as the amount of a constituent nin_{i} divided by the total amount of all constituents in a mixture ntotn_{tot}:


xi=nintot; xeth=nethntot=1020=0.5; xwater=nwaterntot=1020=0.5x_{i} = \frac{n_{i}}{n_{tot}}; \ x_{eth} = \frac{n_{eth}}{n_{tot}} = \frac{10}{20} = 0.5; \ x_{water} = \frac{n_{water}}{n_{tot}} = \frac{10}{20} = 0.5


The sum of all the mole fractions is equal to 1:


i=1Nni=ntot; i=1Nxi=1\sum_{i=1}^{N} n_{i} = n_{tot}; \ \sum_{i=1}^{N} x_{i} = 1


Answer:


xeth=0.5;x_{eth} = 0.5;xwater=0.5;x_{water} = 0.5;i=1Nxi=1\sum_{i=1}^{N} x_{i} = 1

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