Question #20183
You have a container of ice at 0C. What is the minimum mass of ice that must be added to 150.0g of liquid water at 15.0C to lower its temperature to 0.0C?
Expert's answer
Melting ice take the heat from water, hence
L*m(ice) = c*t*m(water)
where L = 335 kJ/kg is specific heat of melting for ice andc = 4200 J/(kg*K) is specific heat capacity.
m(ice) = c*t*m(water)/L = 4200*15*0.15/(335*10^(3)) = 0.0282kg = 28.2 g
L*m(ice) = c*t*m(water)
where L = 335 kJ/kg is specific heat of melting for ice andc = 4200 J/(kg*K) is specific heat capacity.
m(ice) = c*t*m(water)/L = 4200*15*0.15/(335*10^(3)) = 0.0282kg = 28.2 g
